WebNov 18, 2024 · filter (any (...)) evaluates at the group_by () level, filter (...) evaluates at the rowwise () level, even when preceded by group_by (). Hence use: df %>% group_by (Group) %>% filter (any (Value==4)) Group Value 1 B 3 2 B 4 Interestingly, the same appear with mutate, compare: WebApr 13, 2024 · I know that if you want to filter a dataframe if it has some certain strings you can do as follows: df <- df %>% filter (grepl ('first second', Text)) And this will filter the rows including first and second as keywords only. How can I filter the rows excluding the above two keywords? r Share Improve this question Follow asked Apr 13, 2024 at 12:23
r - Opposite of %in%: exclude rows with values specified in a …
WebJun 26, 2024 · We often want to operate only on a specific subset of rows of a data frame. The dplyr filter() function provides a flexible way to extract the rows of interest based on multiple conditions.. Use the filter() function to sort out the rows of a data frame that fulfill a specified condition; Filter a data frame by multiple conditions; filter(my_data_frame, … WebMay 30, 2024 · The filter () method in R can be applied to both grouped and ungrouped data. The expressions include comparison operators (==, >, >= ) , logical operators (&, , … future of prince harry
dplyr filter(): Filter/Select Rows based on conditions
WebJun 14, 2024 · Example 2: Using ‘And’ to Filter Rows. We may also look for rows with Droid as the species and red as the eye color. Quantiles by Group calculation in R with … WebNov 5, 2016 · 2 Answers Sorted by: 16 duplicated can be applied on the whole dataset and this can be done with just base R methods. ex [duplicated (ex) duplicated (ex, fromLast = TRUE),] Using dplyr, we can group_by both the columns and filter only when the number of rows ( n ()) is greater than 1. ex %>% group_by (id, day) %>% filter (n ()>1) Share WebMar 23, 2024 · Here is a version using filter in dplyr that applies the same technique as the accepted answer by negating the logical with !: D2 <- D1 %>% dplyr::filter (!V1 %in% c ('B','N','T')) Share Improve this answer Follow edited Jun 28, 2024 at 20:37 answered May 17, 2024 at 0:34 user29609 1,971 18 22 Add a comment 35 If you look at the code of %in% gj dictionary\u0027s